What is 1/7 \times (3-1/5) ?

The solution to 1/7 \times (3-1/5) is 2/5

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1/7 \times (3-1/5)

\frac{1}{7} \cdot (3 - \frac{1}{5})

\frac{2}{5}

Solution steps

\frac{1}{7} (3 - \frac{1}{5})

Follow the PEMDAS order of operations

Calculate within parentheses

(3 - \frac{1}{5}) : \frac{14}{5}

3 - \frac{1}{5}

3 - \frac{1}{5} = \frac{14}{5}

3 - \frac{1}{5}

Convert element to fraction:

3 = \frac{3 \cdot 5}{5}

= \frac{3 \cdot 5}{5} - \frac{1}{5}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{3 \cdot 5 - 1}{5}

3 \cdot 5 - 1 = 14

3 \cdot 5 - 1

Multiply the numbers:

3 \cdot 5 = 15

= 15 - 1

Subtract the numbers:

15 - 1 = 14

= 14

= \frac{14}{5}

= \frac{14}{5}

= \frac{1}{7} \cdot \frac{14}{5}

Multiply and divide (left to right)

\frac{1}{7} \cdot \frac{14}{5} : \frac{2}{5}

\frac{1}{7} \cdot \frac{14}{5}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{1 \cdot 14}{7 \cdot 5}

\frac{1 \cdot 14}{7 \cdot 5} = \frac{2}{5}

\frac{1 \cdot 14}{7 \cdot 5}

Multiply the numbers:

1 \cdot 14 = 14

= \frac{14}{7 \cdot 5}

Factor the number:

14 = 7 \cdot 2

= \frac{7 \cdot 2}{7 \cdot 5}

Cancel the common factor:

7

= \frac{2}{5}

= \frac{2}{5}

= \frac{2}{5}

(- 6 - 2)^{2}

40 - 32 \div 8 + 5 \cdot (- 2)

3 - 2 - [4 - (6 + 4) - 9 + (1 - 3) - 8] + 4

1 - \frac{5}{6} + \frac{3}{8} - \frac{5}{12}

3^{3} \times 2