The solution to 3/4 (1)-1 is -1/4

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3/4 (1)-1

Solution

\frac{3}{4} (1) - 1

- \frac{1}{4}

Solution steps

\frac{3}{4} (1) - 1

Follow the PEMDAS order of operations

Multiply and divide (left to right)

\frac{3}{4} (1) : \frac{3}{4}

\frac{3}{4} (1)

Apply rule:

(a) = a

(1) = 1

= \frac{3}{4} \cdot 1

Multiply the numbers:

\frac{3}{4} \cdot 1 = \frac{3}{4}

= \frac{3}{4}

= \frac{3}{4} - 1

Add and subtract (left to right)

\frac{3}{4} - 1 : - \frac{1}{4}

\frac{3}{4} - 1

\frac{3}{4} - 1 = - \frac{1}{4}

\frac{3}{4} - 1

Convert element to fraction:

1 = \frac{1 \cdot 4}{4}

= - \frac{1 \cdot 4}{4} + \frac{3}{4}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 1 \cdot 4 + 3}{4}

- 1 \cdot 4 + 3 = - 1

- 1 \cdot 4 + 3

Multiply the numbers:

1 \cdot 4 = 4

= - 4 + 3

Add/Subtract the numbers:

- 4 + 3 = - 1

= - 1

= \frac{- 1}{4}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{1}{4}

= - \frac{1}{4}

= - \frac{1}{4}

2 (3) + 3

12 (6)^{2}

4^{3} - 7

\frac{1}{2} + \frac{1}{3}

2 5^{2} + 2 4^{2}