The solution to 2-(1+2/3) is 1/3

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2-(1+2/3)

Solution

2 - (1 + \frac{2}{3})

\frac{1}{3}

Solution steps

2 - (1 + \frac{2}{3})

Follow the PEMDAS order of operations

Calculate within parentheses

(1 + \frac{2}{3}) : \frac{5}{3}

1 + \frac{2}{3}

1 + \frac{2}{3} = \frac{5}{3}

1 + \frac{2}{3}

Convert element to fraction:

1 = \frac{1 \cdot 3}{3}

= \frac{1 \cdot 3}{3} + \frac{2}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 \cdot 3 + 2}{3}

1 \cdot 3 + 2 = 5

1 \cdot 3 + 2

Multiply the numbers:

1 \cdot 3 = 3

= 3 + 2

Add the numbers:

3 + 2 = 5

= 5

= \frac{5}{3}

= \frac{5}{3}

= 2 - \frac{5}{3}

Add and subtract (left to right)

2 - \frac{5}{3} : \frac{1}{3}

2 - \frac{5}{3}

2 - \frac{5}{3} = \frac{1}{3}

2 - \frac{5}{3}

Convert element to fraction:

2 = \frac{2 \cdot 3}{3}

= \frac{2 \cdot 3}{3} - \frac{5}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 \cdot 3 - 5}{3}

2 \cdot 3 - 5 = 1

2 \cdot 3 - 5

Multiply the numbers:

2 \cdot 3 = 6

= 6 - 5

Subtract the numbers:

6 - 5 = 1

= 1

= \frac{1}{3}

= \frac{1}{3}

= \frac{1}{3}

5 (- 16 \div (21 - 13) - 3 \times (- 7 + 15))

(- 2 - 3)^{3}

5 (6) - \frac{6}{2}

\frac{3}{2} (2)^{1}

- 4^{2} + 5 (- 4) + 7