What is [(2-3)\times 2+3\times (-2+1)]\div (-1-4) ?

The solution to [(2-3)\times 2+3\times (-2+1)]\div (-1-4) is 1

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[(2-3)\times 2+3\times (-2+1)]\div (-1-4)

[(2 - 3) \times 2 + 3 \times (- 2 + 1)] \div (- 1 - 4)

1

Solution steps

[(2 - 3) \times 2 + 3 \times (- 2 + 1)] \div (- 1 - 4)

Follow the PEMDAS order of operations

Calculate within parentheses

[(2 - 3) \times 2 + 3 \times (- 2 + 1)] : - 5

= - 5 \div (- 1 - 4)

Calculate within parentheses

(- 1 - 4) : - 5

= - 5 \div (- 5)

Multiply and divide (left to right)

- 5 \div (- 5) : 1

= 1

6 + \frac{4}{3} - \frac{2}{5}

8 - 2 - 3

5^{11} + 5^{11} + 5^{11} + 5^{11} + 5^{11}

8 - 3 - 5

(- 1)^{2} - 16

What is [(2-3)\times 2+3\times (-2+1)]\div (-1-4) ?
The solution to [(2-3)\times 2+3\times (-2+1)]\div (-1-4) is 1