What is {5-2[4-(6\div 2)]^2}^2 ?

The solution to {5-2[4-(6\div 2)]^2}^2 is 9

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{5-2[4-(6\div 2)]^2}^2

{5 - 2 [4 - (6 \div 2)]^{2}}^{2}

9

Solution steps

{5 - 2 [4 - (6 \div 2)]^{2}}^{2}

Follow the PEMDAS order of operations

Calculate within parentheses

{5 - 2 [4 - (6 \div 2)]^{2}} : 3

5 - 2 [4 - (6 \div 2)]^{2}

Calculate within parentheses

[4 - (6 \div 2)] : 1

4 - (6 \div 2)

Calculate within parentheses

(6 \div 2) : 3

6 \div 2

6 \div 2 = 3

= 3

= 4 - 3

Add and subtract (left to right)

4 - 3 : 1

4 - 3

4 - 3 = 1

= 1

= 1

= 5 - 2 \cdot 1^{2}

Calculate exponents

1^{2} : 1

1^{2}

1^{2} = 1

= 1

= 5 - 2 \cdot 1

Multiply and divide (left to right)

2 \cdot 1 : 2

2 \cdot 1

2 \cdot 1 = 2

= 2

= 5 - 2

Add and subtract (left to right)

5 - 2 : 3

5 - 2

5 - 2 = 3

= 3

= 3

= 3^{2}

Calculate exponents

3^{2} : 9

3^{2}

3^{2} = 9

= 9

= 9

3 (- 1)^{2} - 12 (- 1)

- 90 + [(45 - 23 \times 2 + 5) \times 4]

9 \times (- 2^{2}) - 4 \times (- 2) - 3

(- 9)^{2} - 2 - (- 3) - 6

\frac{1 + 9 \cdot 8 - 2}{- 7 ( 9 - 8 \div ( 4 + 7 ) )}