What is -1^3-3(-1)^2+(-1)-2 ?

The solution to -1^3-3(-1)^2+(-1)-2 is -7

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-1^3-3(-1)^2+(-1)-2

- 1^{3} - 3 (- 1)^{2} + (- 1) - 2

- 7

Solution steps

- 1^{3} - 3 (- 1)^{2} + (- 1) - 2

Follow the PEMDAS order of operations

Calculate exponents

1^{3} : 1

1^{3}

1^{3} = 1

= 1

= - 1 - 3 (- 1)^{2} + (- 1) - 2

Calculate exponents

(- 1)^{2} : 1

(- 1)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 1)^{2} = 1^{2} = 1

= 1

= - 1 - 3 \cdot 1 + (- 1) - 2

Multiply and divide (left to right)

3 \cdot 1 : 3

3 \cdot 1

3 \cdot 1 = 3

= 3

= - 1 - 3 + (- 1) - 2

Add and subtract (left to right)

- 1 - 3 + (- 1) - 2 : - 7

- 1 - 3 + (- 1) - 2

- 1 - 3 = - 4

= - 4 + (- 1) - 2

Apply rule

+ (- a) = - a

+ (- 1) = - 1

= - 4 - 1 - 2

- 4 - 1 = - 5

= - 5 - 2

- 5 - 2 = - 7

= - 7

= - 7

10 (- 1)^{2}

1 + 3 \div 7

3 \cdot 2^{2} + 4 (3 - 1)

3 \times 6^{2} - 6 \times 5 + 6

1 (3 - 8) + [5 - (- 2)]