What is (2)^4-3(2)^2+3 ?

The solution to (2)^4-3(2)^2+3 is 7

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(2)^4-3(2)^2+3

(2)^{4} - 3 (2)^{2} + 3

7

Solution steps

(2)^{4} - 3 (2)^{2} + 3

Follow the PEMDAS order of operations

Calculate exponents

(2)^{4} : 16

(2)^{4}

(2)^{4} = 16

= 16

= 16 - 3 (2)^{2} + 3

Calculate exponents

(2)^{2} : 4

(2)^{2}

(2)^{2} = 4

= 4

= 16 - 3 \cdot 4 + 3

Multiply and divide (left to right)

3 \cdot 4 : 12

3 \cdot 4

3 \cdot 4 = 12

= 12

= 16 - 12 + 3

Add and subtract (left to right)

16 - 12 + 3 : 7

16 - 12 + 3

16 - 12 = 4

= 4 + 3

4 + 3 = 7

= 7

= 7

37 + (- 15) + (- 12) + 21 + (- 10) - 3

- \frac{5}{6} - \frac{1}{6} + 1 - \frac{3}{8}

\frac{3 ^{23} + 3 ^{21} - 3 ^{22}}{21}

12 \div 4 + 5 \times 2 - 3 + 8 \div 2

2 (3)^{2} + 4