What is -19+(-9\times 12+8)\div (-8+33) ?

The solution to -19+(-9\times 12+8)\div (-8+33) is -23

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-19+(-9\times 12+8)\div (-8+33)

- 19 + (- 9 \times 12 + 8) \div (- 8 + 33)

- 23

Solution steps

- 19 + (- 9 \times 12 + 8) \div (- 8 + 33)

Follow the PEMDAS order of operations

Calculate within parentheses

(- 9 \times 12 + 8) : - 100

- 9 \times 12 + 8

Multiply and divide (left to right)

- 9 \times 12 : - 108

- 9 \times 12

- 9 \times 12 = - 108

= - 108

= - 108 + 8

Add and subtract (left to right)

- 108 + 8 : - 100

- 108 + 8

- 108 + 8 = - 100

= - 100

= - 100

= - 19 - 100 \div (- 8 + 33)

Calculate within parentheses

(- 8 + 33) : 25

- 8 + 33

- 8 + 33 = 25

= 25

= - 19 - 100 \div (- 8 + 33)

Multiply and divide (left to right)

100 \div (- 8 + 33) : \frac{100}{( - 8 + 33 )}

100 \div (- 8 + 33)

Apply rule

a \div (- b) = - a \div b

100 \div (- 8 + 33) = - 100 \div 8 + 33 = \frac{100}{( - 8 + 33 )}

= \frac{100}{( - 8 + 33 )}

= - 19 - \frac{100}{( - 8 + 33 )}

Add and subtract (left to right)

- 19 - \frac{100}{( - 8 + 33 )} : - 23

- 19 - \frac{100}{( - 8 + 33 )}

- 19 - \frac{100}{( - 8 + 33 )} = - 23

- 19 - \frac{100}{- 8 + 33}

\frac{100}{- 8 + 33} = 4

\frac{100}{- 8 + 33}

Add/Subtract the numbers:

- 8 + 33 = 25

= \frac{100}{25}

Divide the numbers:

\frac{100}{25} = 4

= 4

= - 19 - 4

Subtract the numbers:

- 19 - 4 = - 23

= - 23

= - 23

= - 23

2 (2)^{2} + 4 (2)

(3 \times + 7) (3 \times (- 7))

5^{4} \times 5

5 \cdot 2^{1}

2 (1)^{2} - 4 (1) + 3

What is -19+(-9\times 12+8)\div (-8+33) ?
The solution to -19+(-9\times 12+8)\div (-8+33) is -23