What is (2+2/5)\div 3/5 ?

The solution to (2+2/5)\div 3/5 is 4

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(2+2/5)\div 3/5

(2 + \frac{2}{5}) \div \frac{3}{5}

4

Solution steps

(2 + \frac{2}{5}) \div \frac{3}{5}

Follow the PEMDAS order of operations

Calculate within parentheses

(2 + \frac{2}{5}) : \frac{12}{5}

2 + \frac{2}{5}

2 + \frac{2}{5} = \frac{12}{5}

2 + \frac{2}{5}

Convert element to fraction:

2 = \frac{2 \cdot 5}{5}

= \frac{2 \cdot 5}{5} + \frac{2}{5}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 \cdot 5 + 2}{5}

2 \cdot 5 + 2 = 12

2 \cdot 5 + 2

Multiply the numbers:

2 \cdot 5 = 10

= 10 + 2

Add the numbers:

10 + 2 = 12

= 12

= \frac{12}{5}

= \frac{12}{5}

= \frac{12}{5} \div \frac{3}{5}

Multiply and divide (left to right)

\frac{12}{5} \div \frac{3}{5} : 4

\frac{12}{5} \div \frac{3}{5}

Apply the fraction rule:

\frac{a}{b} \div \frac{c}{d} = \frac{a}{b} \times \frac{d}{c}

= \frac{12}{5} \cdot \frac{5}{3}

Multiply fractions:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{12 \cdot 5}{5 \cdot 3}

Cancel the common factor:

5

= \frac{12}{3}

Divide the numbers:

\frac{12}{3} = 4

= 4

= 4

(0 + 4)^{2}

(31 + 2) (31 - 2)

2 + 4 \times 20 (10 - 15)

\frac{3}{4} \cdot 2 + 3

3 \times (2 \times 64) \div 4