What is 40/4+2*6/4-3 ?

The solution to 40/4+2*6/4-3 is 10

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40/4+2*6/4-3

\frac{40}{4} + 2 \cdot \frac{6}{4} - 3

10

Solution steps

\frac{40}{4} + 2 \cdot \frac{6}{4} - 3

\frac{40}{4} = 10

Divide the numbers:

\frac{40}{4} = 10

10

= 10 + 2 \cdot \frac{6}{4} - 3

\frac{6}{4} = \frac{3}{2}

Cancel the common factor:

2

\frac{3}{2}

= 10 + 2 \cdot \frac{3}{2} - 3

Follow the PEMDAS order of operations

Multiply and divide (left to right)

2 \cdot \frac{3}{2} : 3

2 \cdot \frac{3}{2}

Convert element to fraction:

2 = \frac{2}{1}

= \frac{2}{1} \cdot \frac{3}{2}

Cross-cancel common factor:

2

= \frac{3}{1}

Divide the numbers:

\frac{3}{1} = 3

= 3

= 10 + 3 - 3

Add and subtract (left to right)

10 + 3 - 3 : 10

10 + 3 - 3

10 + 3 = 13

= 13 - 3

13 - 3 = 10

= 10

= 10

(2 + 1)^{2}

- 54 - (- 37 - 15)

64 - 16

0.27

\frac{1}{0.007}