What is (1/3)(-3)^2 ?

The solution to (1/3)(-3)^2 is 3

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(1/3)(-3)^2

(\frac{1}{3}) (- 3)^{2}

3

Solution steps

(\frac{1}{3}) (- 3)^{2}

Follow the PEMDAS order of operations

Calculate exponents

(- 3)^{2} : 9

(- 3)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 3)^{2} = 3^{2} = 9

= 9

= (\frac{1}{3}) \cdot 9

Multiply and divide (left to right)

(\frac{1}{3}) \cdot 9 : 3

(\frac{1}{3}) \cdot 9

Apply rule:

(a) = a

(\frac{1}{3}) = \frac{1}{3}

= \frac{1}{3} \cdot 9

\frac{1}{3} \cdot 9 = 3

\frac{1}{3} \cdot 9

Convert element to fraction:

9 = \frac{9}{1}

= \frac{1}{3} \cdot \frac{9}{1}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{1 \cdot 9}{3 \cdot 1}

\frac{1 \cdot 9}{3 \cdot 1} = 3

\frac{1 \cdot 9}{3 \cdot 1}

\frac{1 \cdot 9}{3 \cdot 1} = \frac{9}{3}

\frac{1 \cdot 9}{3 \cdot 1}

Multiply the numbers:

1 \cdot 9 = 9

= \frac{9}{3 \cdot 1}

Multiply the numbers:

3 \cdot 1 = 3

= \frac{9}{3}

= \frac{9}{3}

Divide the numbers:

\frac{9}{3} = 3

= 3

= 3

= 3

= 3

3^{5} \cdot 5

(9 \times + 11) + (10 \times + 5)

3 \times 8 - 15 \div 3

26 + 5 \cdot 10 + (- 10)

2 \cdot 2^{3} - 3