What is -5(1/3+2)+6 ?

The solution to -5(1/3+2)+6 is -17/3

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-5(1/3+2)+6

- 5 (\frac{1}{3} + 2) + 6

- \frac{17}{3}

Solution steps

- 5 (\frac{1}{3} + 2) + 6

Follow the PEMDAS order of operations

Calculate within parentheses

(\frac{1}{3} + 2) : \frac{7}{3}

\frac{1}{3} + 2

\frac{1}{3} + 2 = \frac{7}{3}

\frac{1}{3} + 2

Convert element to fraction:

2 = \frac{2 \cdot 3}{3}

= \frac{2 \cdot 3}{3} + \frac{1}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 \cdot 3 + 1}{3}

2 \cdot 3 + 1 = 7

2 \cdot 3 + 1

Multiply the numbers:

2 \cdot 3 = 6

= 6 + 1

Add the numbers:

6 + 1 = 7

= 7

= \frac{7}{3}

= \frac{7}{3}

= - 5 \cdot \frac{7}{3} + 6

Multiply and divide (left to right)

- 5 \cdot \frac{7}{3} : - \frac{35}{3}

- 5 \cdot \frac{7}{3}

Convert element to fraction:

5 = \frac{5}{1}

= - \frac{5}{1} \cdot \frac{7}{3}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

\frac{5}{1} \cdot \frac{7}{3} = \frac{5 \cdot 7}{1 \cdot 3}

= - \frac{5 \cdot 7}{1 \cdot 3}

Multiply the numbers:

5 \cdot 7 = 35

= - \frac{35}{1 \cdot 3}

Multiply the numbers:

1 \cdot 3 = 3

= - \frac{35}{3}

= - \frac{35}{3} + 6

Add and subtract (left to right)

- \frac{35}{3} + 6 : - \frac{17}{3}

- \frac{35}{3} + 6

- \frac{35}{3} + 6 = - \frac{17}{3}

- \frac{35}{3} + 6

Convert element to fraction:

6 = \frac{6 \cdot 3}{3}

= \frac{6 \cdot 3}{3} - \frac{35}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{6 \cdot 3 - 35}{3}

6 \cdot 3 - 35 = - 17

6 \cdot 3 - 35

Multiply the numbers:

6 \cdot 3 = 18

= 18 - 35

Subtract the numbers:

18 - 35 = - 17

= - 17

= \frac{- 17}{3}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{17}{3}

= - \frac{17}{3}

= - \frac{17}{3}

4 (1)^{3} - 12 (1)^{2}

4^{2} \cdot 2

81 \div 3 \times 50

4 \cdot 5^{3}

2^{2} + 13