What is -(-4)^2-5(-4)+1 ?

The solution to -(-4)^2-5(-4)+1 is 5

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-(-4)^2-5(-4)+1

- (- 4)^{2} - 5 (- 4) + 1

5

Solution steps

- (- 4)^{2} - 5 (- 4) + 1

Follow the PEMDAS order of operations

Calculate exponents

(- 4)^{2} : 16

(- 4)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 4)^{2} = 4^{2} = 16

= 16

= - 16 - 5 (- 4) + 1

Multiply and divide (left to right)

5 (- 4) : - 20

5 (- 4)

Apply rule

a \cdot (- b) = - a \cdot b

5 (- 4) = - 5 \cdot 4 = - 20

= - 20

= - 16 - (- 20) + 1

Add and subtract (left to right)

- 16 - (- 20) + 1 : 5

- 16 - (- 20) + 1

Apply rule

- (- a) = + a

- (- 20) = + 20

= - 16 + 20 + 1

- 16 + 20 = 4

= 4 + 1

4 + 1 = 5

= 5

= 5

\frac{1 ^{3} + 4 ( 1 )}{1}

3 - 4 - 2

3 - 5 - 2

343 \frac{1}{3} + 625 \frac{1}{4} - 2^{2}

\frac{2}{3} + 2 - \frac{- 3}{5}