What is (-1)^4-15(-1)^2+10(-1)+24 ?

The solution to (-1)^4-15(-1)^2+10(-1)+24 is 0

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(-1)^4-15(-1)^2+10(-1)+24

(- 1)^{4} - 15 (- 1)^{2} + 10 (- 1) + 24

0

Solution steps

(- 1)^{4} - 15 (- 1)^{2} + 10 (- 1) + 24

Follow the PEMDAS order of operations

Calculate exponents

(- 1)^{4} : 1

(- 1)^{4}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 1)^{4} = 1^{4} = 1

= 1

= 1 - 15 (- 1)^{2} + 10 (- 1) + 24

Calculate exponents

(- 1)^{2} : 1

(- 1)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 1)^{2} = 1^{2} = 1

= 1

= 1 - 15 \cdot 1 + 10 (- 1) + 24

Multiply and divide (left to right)

15 \cdot 1 : 15

15 \cdot 1

15 \cdot 1 = 15

= 15

= 1 - 15 + 10 (- 1) + 24

Multiply and divide (left to right)

10 (- 1) : - 10

10 (- 1)

Apply rule

a \cdot (- b) = - a \cdot b

10 (- 1) = - 10 \cdot 1 = - 10

= - 10

= 1 - 15 - 10 + 24

Add and subtract (left to right)

1 - 15 - 10 + 24 : 0

1 - 15 - 10 + 24

1 - 15 = - 14

= - 14 - 10 + 24

- 14 - 10 = - 24

= - 24 + 24

- 24 + 24 = 0

= 0

= 0

7 \div (5 \times 2 - (6 \div 3))

213 + 321969 - 332162

4 \div (5 \frac{1}{3} + 2 \frac{2}{3})

(- 3)^{2} + 3 (- 3)

18 + 7 \times 9 + 5

What is (-1)^4-15(-1)^2+10(-1)+24 ?
The solution to (-1)^4-15(-1)^2+10(-1)+24 is 0