What is (4/5-1/2)-(-4-1) ?

The solution to (4/5-1/2)-(-4-1) is 5 3/10

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Popular >

(4/5-1/2)-(-4-1)

Solution

(\frac{4}{5} - \frac{1}{2}) - (- 4 - 1)

Solution

5 \frac{3}{10}

Solution steps

(\frac{4}{5} - \frac{1}{2}) - (- 4 - 1)

Follow the PEMDAS order of operations

Calculate within parentheses

(\frac{4}{5} - \frac{1}{2}) : \frac{3}{10}

\frac{4}{5} - \frac{1}{2}

\frac{4}{5} - \frac{1}{2} = \frac{3}{10}

\frac{4}{5} - \frac{1}{2}

Least Common Multiplier of

5, 2 : 10

5, 2

Least Common Multiplier (LCM)

Prime factorization of

5 : 5

5

5

is a prime number, therefore no factorization is possible

= 5

Prime factorization of

2 : 2

2

2

is a prime number, therefore no factorization is possible

= 2

Multiply each factor the greatest number of times it occurs in either

5

2

= 5 \cdot 2

Multiply the numbers:

5 \cdot 2 = 10

= 10

Adjust Fractions based on the LCM

Multiply each numerator by the same amount needed to multiply its

corresponding denominator to turn it into the LCM

10

For

\frac{4}{5} :

multiply the denominator and numerator by

2

\frac{4}{5} = \frac{4 \cdot 2}{5 \cdot 2} = \frac{8}{10}

For

\frac{1}{2} :

multiply the denominator and numerator by

5

\frac{1}{2} = \frac{1 \cdot 5}{2 \cdot 5} = \frac{5}{10}

= \frac{8}{10} - \frac{5}{10}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{8 - 5}{10}

Subtract the numbers:

8 - 5 = 3

= \frac{3}{10}

= \frac{3}{10}

= \frac{3}{10} - (- 4 - 1)

Calculate within parentheses

(- 4 - 1) : - 5

- 4 - 1

- 4 - 1 = - 5

= - 5

= \frac{3}{10} - (- 5)

Add and subtract (left to right)

\frac{3}{10} - (- 5) : \frac{53}{10}

\frac{3}{10} - (- 5)

Apply rule

- (- a) = + a

- (- 5) = + 5

= \frac{3}{10} + 5

\frac{3}{10} + 5 = \frac{53}{10}

\frac{3}{10} + 5

Convert element to fraction:

5 = \frac{5 \cdot 10}{10}

= \frac{5 \cdot 10}{10} + \frac{3}{10}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{5 \cdot 10 + 3}{10}

5 \cdot 10 + 3 = 53

5 \cdot 10 + 3

Multiply the numbers:

5 \cdot 10 = 50

= 50 + 3

Add the numbers:

50 + 3 = 53

= 53

= \frac{53}{10}

= \frac{53}{10}

= \frac{53}{10}

Convert improper fractions to mixed numbers:

\frac{53}{10} = 5 \frac{3}{10}

\frac{53}{10} = 5

Remainder

3

\frac{53}{10}

Write the problem in long division format

10 \overline{∣ 53}

Divide

53

10

to get

5

Divide

53

10

to get

5

5 10 \overline{∣ 53}

Multiply the quotient digit

(5)

by the divisor

10

5 10 \overline{∣ 53} \underline{50}

Subtract

50

from

53

5 10 \overline{∣ 53} \underline{50} 3

5 10 \overline{∣ 53} \underline{50} 3

The solution for Long Division of

\frac{53}{10}

5

with remainder of

3

5 Remainder 3

Convert to mixed number: Quotient

\frac{Remainder}{Divisor}

\frac{53}{10} = 5 \frac{3}{10}

= 5 \frac{3}{10}

= 5 \frac{3}{10}

Popular Examples

4\div 3-57

4 \div 3 - 57

90(100)+500

90 (100) + 500

(35-4)\times 3+15\div 3

(35 - 4) \times 3 + 15 \div 3

250\div 5\div 10*2

250 \div 5 \div 10 \cdot 2

39^2+52^2

3 9^{2} + 5 2^{2}

Frequently Asked Questions (FAQ)

What is (4/5-1/2)-(-4-1) ?
The solution to (4/5-1/2)-(-4-1) is 5 3/10