What is -4^2+(2\times (-4))-8 ?

The solution to -4^2+(2\times (-4))-8 is -32

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-4^2+(2\times (-4))-8

- 4^{2} + (2 \cdot (- 4)) - 8

- 32

Solution steps

- 4^{2} + (2 (- 4)) - 8

Follow the PEMDAS order of operations

Calculate within parentheses

(2 \cdot (- 4)) : - 8

2 (- 4)

Apply rule

a \cdot (- b) = - a \cdot b

2 (- 4) = - 2 \cdot 4 = - 8

= - 8

= - 4^{2} - 8 - 8

Calculate exponents

4^{2} : 16

4^{2}

4^{2} = 16

= 16

= - 16 - 8 - 8

Add and subtract (left to right)

- 16 - 8 - 8 : - 32

- 16 - 8 - 8

- 16 - 8 = - 24

= - 24 - 8

- 24 - 8 = - 32

= - 32

= - 32

5^{2} \cdot 5

5^{2} \cdot 3

- 6 + 8 - 3

6^{2} + 3^{4}

\frac{1}{2} \times 2 + 3