What is (-2)^3+(-3)^2-(-1)^2-(-2)^3 ?

The solution to (-2)^3+(-3)^2-(-1)^2-(-2)^3 is 8

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(-2)^3+(-3)^2-(-1)^2-(-2)^3

(- 2)^{3} + (- 3)^{2} - (- 1)^{2} - (- 2)^{3}

8

Solution steps

(- 2)^{3} + (- 3)^{2} - (- 1)^{2} - (- 2)^{3}

Follow the PEMDAS order of operations

Calculate exponents

(- 2)^{3} : - 8

(- 2)^{3}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 2)^{3} = - 2^{3} = - 8

= - 8

= - 8 + (- 3)^{2} - (- 1)^{2} - (- 2)^{3}

Calculate exponents

(- 3)^{2} : 9

(- 3)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 3)^{2} = 3^{2} = 9

= 9

= - 8 + 9 - (- 1)^{2} - (- 2)^{3}

Calculate exponents

(- 1)^{2} : 1

(- 1)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 1)^{2} = 1^{2} = 1

= 1

= - 8 + 9 - 1 - (- 2)^{3}

Calculate exponents

(- 2)^{3} : - 8

(- 2)^{3}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 2)^{3} = - 2^{3} = - 8

= - 8

= - 8 + 9 - 1 - (- 8)

Add and subtract (left to right)

- 8 + 9 - 1 - (- 8) : 8

- 8 + 9 - 1 - (- 8)

- 8 + 9 = 1

= 1 - 1 - (- 8)

1 - 1 = 0

= 0 - (- 8)

Apply rule

- (- a) = + a

- (- 8) = + 8

= 0 + 8

0 + 8 = 8

= 8

= 8

\frac{9}{35} - (\frac{4}{21} + \frac{8}{15})

10 - [6 + (2 + 7)]

- (2)^{2} - 2 (2) - 4

4 \times (50 \div 5) + 15 - (6 \times 3 + 8) - 16

7 \times (6 - (- 5)) - 4 \times (5 - 3)

What is (-2)^3+(-3)^2-(-1)^2-(-2)^3 ?
The solution to (-2)^3+(-3)^2-(-1)^2-(-2)^3 is 8