What is (3(-3)^2+4(-2)^3)/(2^3-3^2) ?

The solution to (3(-3)^2+4(-2)^3)/(2^3-3^2) is 5

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(3(-3)^2+4(-2)^3)/(2^3-3^2)

\frac{3 ( - 3 ) ^{2} + 4 ( - 2 ) ^{3}}{2 ^{3} - 3 ^{2}}

5

Solution steps

\frac{3 ( - 3 ) ^{2} + 4 ( - 2 ) ^{3}}{2 ^{3} - 3 ^{2}}

Solve

3 (- 3)^{2} + 4 (- 2)^{3} : - 5

Follow the PEMDAS order of operations

Calculate exponents

(- 3)^{2} : 9

(- 3)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 3)^{2} = 3^{2} = 9

= 9

= 3 \cdot 9 + 4 (- 2)^{3}

Calculate exponents

(- 2)^{3} : - 8

(- 2)^{3}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 2)^{3} = - 2^{3} = - 8

= - 8

= 3 \cdot 9 + 4 (- 8)

Multiply and divide (left to right)

3 \cdot 9 : 27

3 \cdot 9

3 \cdot 9 = 27

= 27

= 27 + 4 (- 8)

Multiply and divide (left to right)

4 (- 8) : - 32

4 (- 8)

Apply rule

a \cdot (- b) = - a \cdot b

4 (- 8) = - 4 \cdot 8 = - 32

= - 32

= 27 - 32

Add and subtract (left to right)

27 - 32 : - 5

27 - 32

27 - 32 = - 5

= - 5

= - 5

Solve

2^{3} - 3^{2} : - 1

Follow the PEMDAS order of operations

Calculate exponents

2^{3} : 8

2^{3}

2^{3} = 8

= 8

= 8 - 3^{2}

Calculate exponents

3^{2} : 9

3^{2}

3^{2} = 9

= 9

= 8 - 9

Add and subtract (left to right)

8 - 9 : - 1

8 - 9

8 - 9 = - 1

= - 1

= - 1

= \frac{- 5}{- 1}

Simplify

\frac{- 5}{- 1} : 5

Apply the fraction rule:

\frac{- a}{- b} = \frac{a}{b}

= \frac{5}{1}

Apply rule

\frac{a}{1} = a

= 5

= 5

(- 112) (- 6) - 72 \div (- 12) + 34

1 5^{2} + 1 0^{2}

36 \times (5 \div 9)

40 - \frac{32}{8} + 5 \cdot + (- 2)

(8 \times 3) \times 3 \div 4 + (8 - 11)

What is (3(-3)^2+4(-2)^3)/(2^3-3^2) ?
The solution to (3(-3)^2+4(-2)^3)/(2^3-3^2) is 5