What is -3^2-[2^3-(5^2-4^3)^0] ?

The solution to -3^2-[2^3-(5^2-4^3)^0] is -16

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-3^2-[2^3-(5^2-4^3)^0]

- 3^{2} - [2^{3} - (5^{2} - 4^{3})^{0}]

- 16

Solution steps

- 3^{2} - [2^{3} - (5^{2} - 4^{3})^{0}]

Follow the PEMDAS order of operations

Calculate within parentheses

[2^{3} - (5^{2} - 4^{3})^{0}] : 7

2^{3} - (5^{2} - 4^{3})^{0}

Calculate within parentheses

(5^{2} - 4^{3}) : - 39

5^{2} - 4^{3}

Calculate exponents

5^{2} : 25

5^{2}

5^{2} = 25

= 25

= 25 - 4^{3}

Calculate exponents

4^{3} : 64

4^{3}

4^{3} = 64

= 64

= 25 - 64

Add and subtract (left to right)

25 - 64 : - 39

25 - 64

25 - 64 = - 39

= - 39

= - 39

= 2^{3} - (- 39)^{0}

Calculate exponents

2^{3} : 8

2^{3}

2^{3} = 8

= 8

= 8 - (- 39)^{0}

Calculate exponents

(- 39)^{0} : 1

(- 39)^{0}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 39)^{0} = 3 9^{0} = 1

= 1

= 8 - 1

Add and subtract (left to right)

8 - 1 : 7

8 - 1

8 - 1 = 7

= 7

= 7

= - 3^{2} - 7

Calculate exponents

3^{2} : 9

3^{2}

3^{2} = 9

= 9

= - 9 - 7

Add and subtract (left to right)

- 9 - 7 : - 16

- 9 - 7

- 9 - 7 = - 16

= - 16

= - 16

((\frac{2}{1}) - 1) \times 100

4 \div 12 \times 8 \div 24

3 (1)^{2} + 2

3 + 11 (9) - 9 (11)

\frac{( - 3 ) ^{2} - 4 ( - 3 ) - 32}{( - 3 ) ^{2} - 4}