What is 2^4+(-2)^4-2^4+2^3+3^3-5^0 ?

The solution to 2^4+(-2)^4-2^4+2^3+3^3-5^0 is 50

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2^4+(-2)^4-2^4+2^3+3^3-5^0

2^{4} + (- 2)^{4} - 2^{4} + 2^{3} + 3^{3} - 5^{0}

50

Solution steps

2^{4} + (- 2)^{4} - 2^{4} + 2^{3} + 3^{3} - 5^{0}

Follow the PEMDAS order of operations

Calculate exponents

2^{4} : 16

2^{4}

2^{4} = 16

= 16

= 16 + (- 2)^{4} - 2^{4} + 2^{3} + 3^{3} - 5^{0}

Calculate exponents

(- 2)^{4} : 16

(- 2)^{4}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{4} = 2^{4} = 16

= 16

= 16 + 16 - 2^{4} + 2^{3} + 3^{3} - 5^{0}

Calculate exponents

2^{4} : 16

2^{4}

2^{4} = 16

= 16

= 16 + 16 - 16 + 2^{3} + 3^{3} - 5^{0}

Calculate exponents

2^{3} : 8

2^{3}

2^{3} = 8

= 8

= 16 + 16 - 16 + 8 + 3^{3} - 5^{0}

Calculate exponents

3^{3} : 27

3^{3}

3^{3} = 27

= 27

= 16 + 16 - 16 + 8 + 27 - 5^{0}

Calculate exponents

5^{0} : 1

5^{0}

5^{0} = 1

= 1

= 16 + 16 - 16 + 8 + 27 - 1

Add and subtract (left to right)

16 + 16 - 16 + 8 + 27 - 1 : 50

16 + 16 - 16 + 8 + 27 - 1

16 + 16 = 32

= 32 - 16 + 8 + 27 - 1

32 - 16 = 16

= 16 + 8 + 27 - 1

16 + 8 = 24

= 24 + 27 - 1

24 + 27 = 51

= 51 - 1

51 - 1 = 50

= 50

= 50

3^{2} + 22 - (- 45)

5 (- 2 - 7)^{2} - 7

\frac{13 + 7 ^{2} \div 7}{9 - 20 \div 4 - 16}

3^{3} \times 5^{0}

2 (2 (2 (2 + 0 + 1 + 9)) 19 + 1)

What is 2^4+(-2)^4-2^4+2^3+3^3-5^0 ?
The solution to 2^4+(-2)^4-2^4+2^3+3^3-5^0 is 50