What is (-2)^2-2(-2)+4 ?

The solution to (-2)^2-2(-2)+4 is 12

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(-2)^2-2(-2)+4

(- 2)^{2} - 2 (- 2) + 4

12

Solution steps

(- 2)^{2} - 2 (- 2) + 4

Follow the PEMDAS order of operations

Calculate exponents

(- 2)^{2} : 4

(- 2)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{2} = 2^{2} = 4

= 4

= 4 - 2 (- 2) + 4

Multiply and divide (left to right)

2 (- 2) : - 4

2 (- 2)

Apply rule

a \cdot (- b) = - a \cdot b

2 (- 2) = - 2 \cdot 2 = - 4

= - 4

= 4 - (- 4) + 4

Add and subtract (left to right)

4 - (- 4) + 4 : 12

4 - (- 4) + 4

Apply rule

- (- a) = + a

- (- 4) = + 4

= 4 + 4 + 4

4 + 4 = 8

= 8 + 4

8 + 4 = 12

= 12

= 12

- 5^{2} + 6 (- 5) + 7

6 - 4 (9 \times 6) 9 \times 1

3^{2} - 32 + 7^{3}

(10 - 7)^{2}

7 + 5 - 8 + 10 \times (- 24) \div 3 + 9 - 3