What is 3(-2)^2-2(-2)+1 ?

The solution to 3(-2)^2-2(-2)+1 is 17

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3(-2)^2-2(-2)+1

3 (- 2)^{2} - 2 (- 2) + 1

17

Solution steps

3 (- 2)^{2} - 2 (- 2) + 1

Follow the PEMDAS order of operations

Calculate exponents

(- 2)^{2} : 4

(- 2)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{2} = 2^{2} = 4

= 4

= 3 \cdot 4 - 2 (- 2) + 1

Multiply and divide (left to right)

3 \cdot 4 : 12

3 \cdot 4

3 \cdot 4 = 12

= 12

= 12 - 2 (- 2) + 1

Multiply and divide (left to right)

2 (- 2) : - 4

2 (- 2)

Apply rule

a \cdot (- b) = - a \cdot b

2 (- 2) = - 2 \cdot 2 = - 4

= - 4

= 12 - (- 4) + 1

Add and subtract (left to right)

12 - (- 4) + 1 : 17

12 - (- 4) + 1

Apply rule

- (- a) = + a

- (- 4) = + 4

= 12 + 4 + 1

12 + 4 = 16

= 16 + 1

16 + 1 = 17

= 17

= 17

(8 + 3 \times 2) - (4 \times (5 + 3) - (- 12 - 3) + 125)

(- 3)^{4} - 4 (- 3)^{2}

(- 16 - (- 3)) \times (- 2)

(- 2)^{2} + 6 (- 2) + 5

9 - \frac{3}{10} - \frac{2}{5}