What is (5-1)^2+(4-(-2)^2) ?

The solution to (5-1)^2+(4-(-2)^2) is 16

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(5-1)^2+(4-(-2)^2)

(5 - 1)^{2} + (4 - (- 2)^{2})

16

Solution steps

(5 - 1)^{2} + (4 - (- 2)^{2})

Follow the PEMDAS order of operations

Calculate within parentheses

(5 - 1) : 4

5 - 1

5 - 1 = 4

= 4

= 4^{2} + (4 - (- 2)^{2})

Calculate within parentheses

(4 - (- 2)^{2}) : 0

4 - (- 2)^{2}

Calculate exponents

(- 2)^{2} : 4

(- 2)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{2} = 2^{2} = 4

= 4

= 4 - 4

Add and subtract (left to right)

4 - 4 : 0

4 - 4

4 - 4 = 0

= 0

= 0

= 4^{2} + 0

Calculate exponents

4^{2} : 16

4^{2}

4^{2} = 16

= 16

= 16 + 0

Add and subtract (left to right)

16 + 0 : 16

16 + 0

16 + 0 = 16

= 16

= 16

3 + 10 (\times 2 + 13 - 6)

(- 16) - (- 15) + 1

4 \times (- 8) + 6 - (- 2)^{3}

2^{1} (2 (2) + 1) - 1

((- 1) + 1)^{2}