What is (-12)\div ((-10)-(+2)) ?

The solution to (-12)\div ((-10)-(+2)) is 1

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(-12)\div ((-10)-(+2))

(- 12) \div ((- 10) - (+ 2))

1

Solution steps

(- 12) \div ((- 10) - (2))

Follow the PEMDAS order of operations

Calculate within parentheses

((- 10) - (2)) : - 12

(- 10) - (2)

(- 10) - (2) = - 12

= - 12

= (- 12) \div (- 12)

Multiply and divide (left to right)

(- 12) \div (- 12) : 1

(- 12) \div (- 12)

Apply rule

(- a) \div (- b) = a \div b

(- 12) \div (- 12) = 12 \div 12 = 1

= 1

= 1

4 \cdot 6^{3}

- \frac{1}{2} (2)^{3}

(2^{2} - 2)^{2}

455 - 730 - 20

(- 2 - 8) 5 + 4