What is the derivative of f(x)= 1/(2x) ?

The derivative of f(x)= 1/(2x) is -1/(2x^2)

What is the first derivative of f(x)= 1/(2x) ?

The first derivative of f(x)= 1/(2x) is -1/(2x^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

f (x) = \frac{1}{2 x}

- \frac{1}{2 x ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{2 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} \frac{d}{d x} (\frac{1}{x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{1}{2} \frac{d}{d x} (x^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{2} (- 1 \cdot x^{- 1 - 1})

Simplify

\frac{1}{2} (- 1 \cdot x^{- 1 - 1}) : - \frac{1}{2 x ^{2}}

= - \frac{1}{2 x ^{2}}

(1, 0)

x e^{- x^{2}}

f (x) = x^{7}

f (x) = 8 - x^{3}

x + y = 3

What is the derivative of f(x)= 1/(2x) ?
The derivative of f(x)= 1/(2x) is -1/(2x^2)
What is the first derivative of f(x)= 1/(2x) ?
The first derivative of f(x)= 1/(2x) is -1/(2x^2)