What is the tangent of f(x)=7x^2+2x-7,\at x=-3 ?

The tangent of f(x)=7x^2+2x-7,\at x=-3 is y=-40x-70

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tangent of f(x)=7x^2+2x-7,\at x=-3

tangent of

f (x) = 7 x^{2} + 2 x - 7, at x = - 3

y = - 40 x - 70

Solution steps

Find the tangent point:

(- 3, 50)

Find the slope of

f (x) = 7 x^{2} + 2 x - 7 : \frac{df ( x )}{d x} = 14 x + 2

Compute the slope of

f (x) = 7 x^{2} + 2 x - 7

x = - 3 : m = - 40

Find the line with slope m=

- 40

and passing through

(- 3, 50) : y = - 40 x - 70

y = - 40 x - 70

- 3 x + 5 y = 2 x + 3 y

(4, - \frac{2 π}{3})

(- 2, \frac{5 π}{4})

0.5 x - 5 y = 9

What is the tangent of f(x)=7x^2+2x-7,\at x=-3 ?
The tangent of f(x)=7x^2+2x-7,\at x=-3 is y=-40x-70