What is the tangent of y=x^3-5x,(-1,4) ?

The tangent of y=x^3-5x,(-1,4) is y=-2x+2

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tangent of y=x^3-5x,(-1,4)

tangent of

y = x^{3} - 5 x, (- 1, 4)

y = - 2 x + 2

Solution steps

Find the slope of

y = x^{3} - 5 x : \frac{d y}{d x} = 3 x^{2} - 5

Compute the slope of

y = x^{3} - 5 x

(- 1, 4) : m = - 2

Find the line with slope m=

- 2

and passing through

(- 1, 4) : y = - 2 x + 2

y = - 2 x + 2

f (x) = e^{x^{2}}

f (x) = 4 x^{2}

3 x + 5 y = 15

f = 2

y, x y = 8

What is the tangent of y=x^3-5x,(-1,4) ?
The tangent of y=x^3-5x,(-1,4) is y=-2x+2