What is the derivative of f(x)= 1/4 x^8-1/2 x^6-x+2 ?

The derivative of f(x)= 1/4 x^8-1/2 x^6-x+2 is 2x^7-3x^5-1

What is the first derivative of f(x)= 1/4 x^8-1/2 x^6-x+2 ?

The first derivative of f(x)= 1/4 x^8-1/2 x^6-x+2 is 2x^7-3x^5-1

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derivative of

f (x) = \frac{1}{4} x^{8} - \frac{1}{2} x^{6} - x + 2

2 x^{7} - 3 x^{5} - 1

Solution steps

\frac{d}{d x} (\frac{1}{4} x^{8} - \frac{1}{2} x^{6} - x + 2)

Simplify

\frac{1}{4} x^{8} - \frac{1}{2} x^{6} - x + 2 : \frac{x ^{8}}{4} - \frac{x ^{6}}{2} - x + 2

= \frac{d}{d x} (\frac{x ^{8}}{4} - \frac{x ^{6}}{2} - x + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{8}}{4}) - \frac{d}{d x} (\frac{x ^{6}}{2}) - \frac{d x}{d x} + \frac{d}{d x} (2)

\frac{d}{d x} (\frac{x ^{8}}{4}) = 2 x^{7}

\frac{d}{d x} (\frac{x ^{6}}{2}) = 3 x^{5}

\frac{d x}{d x} = 1

\frac{d}{d x} (2) = 0

= 2 x^{7} - 3 x^{5} - 1 + 0

Simplify

= 2 x^{7} - 3 x^{5} - 1

y = \frac{4}{x}

x = 6

f (x) = 4 e^{x} cos (x)

f (x) = x^{2} - 4 x

(- 3, \frac{5 π}{6})

What is the derivative of f(x)= 1/4 x^8-1/2 x^6-x+2 ?
The derivative of f(x)= 1/4 x^8-1/2 x^6-x+2 is 2x^7-3x^5-1
What is the first derivative of f(x)= 1/4 x^8-1/2 x^6-x+2 ?
The first derivative of f(x)= 1/4 x^8-1/2 x^6-x+2 is 2x^7-3x^5-1