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Popular >

distance (5,-9),(-4,-1)

Solution

distance

(5, - 9), (- 4, - 1)

Solution

145

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(5, - 9)

and

(- 4, - 1)

is

= (- 4 - 5)^{2} + (- 1 - (- 9))^{2}

Simplify

= 145

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tangent of f(x)=(1+x)^{4/x},\at x=1 tangent of

f (x) = (1 + x)^{\frac{4}{x}}, at x = 1

cartesian (6,-(7pi)/6)polar to cartesian

(6, - \frac{7 π}{6})

derivative of f(x)=e^xln(x)derivative of

f (x) = e^{x} ln (x)

Frequently Asked Questions (FAQ)

What is the distance (5,-9),(-4,-1) ?
The distance (5,-9),(-4,-1) is square root of 145