What is the derivative of f(x)=x^2+x-5 ?

The derivative of f(x)=x^2+x-5 is 2x+1

What is the first derivative of f(x)=x^2+x-5 ?

The first derivative of f(x)=x^2+x-5 is 2x+1

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derivative of

f (x) = x^{2} + x - 5

2 x + 1

Solution steps

\frac{d}{d x} (x^{2} + x - 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d x}{d x} - \frac{d}{d x} (5)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d x}{d x} = 1

\frac{d}{d x} (5) = 0

= 2 x + 1 - 0

Simplify

= 2 x + 1

y = x^{2} - x + 7

x = 9

2 x + y = 6

f (x) = 1 - x^{2}

x^{3} sec (x) + sec (x) tan (x) x^{4}

What is the derivative of f(x)=x^2+x-5 ?
The derivative of f(x)=x^2+x-5 is 2x+1
What is the first derivative of f(x)=x^2+x-5 ?
The first derivative of f(x)=x^2+x-5 is 2x+1