What is the tangent of x^2+3x-5,\at x=1 ?

The tangent of x^2+3x-5,\at x=1 is y=5x-6

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tangent of x^2+3x-5,\at x=1

tangent of

x^{2} + 3 x - 5, at x = 1

y = 5 x - 6

Solution steps

Find the tangent point:

(1, - 1)

Find the slope of

y = x^{2} + 3 x - 5 : \frac{d y}{d x} = 2 x + 3

Compute the slope of

y = x^{2} + 3 x - 5

x = 1 : m = 5

Find the line with slope m=

5

and passing through

(1, - 1) : y = 5 x - 6

y = 5 x - 6

y = 7 x

x + \frac{1}{x}

y = 5 x^{2}

f (x) = e^{- x + 2}, at x = 4

y = 2 x + 4

What is the tangent of x^2+3x-5,\at x=1 ?
The tangent of x^2+3x-5,\at x=1 is y=5x-6