What is the derivative of y=(x^2+3)^2 ?

The derivative of y=(x^2+3)^2 is 4x(x^2+3)

What is the first derivative of y=(x^2+3)^2 ?

The first derivative of y=(x^2+3)^2 is 4x(x^2+3)

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derivative of

y = (x^{2} + 3)^{2}

4 x (x^{2} + 3)

Solution steps

\frac{d}{d x} ((x^{2} + 3)^{2})

Apply the chain rule:

2 (x^{2} + 3) \frac{d}{d x} (x^{2} + 3)

= 2 (x^{2} + 3) \frac{d}{d x} (x^{2} + 3)

\frac{d}{d x} (x^{2} + 3) = 2 x

= 2 (x^{2} + 3) \cdot 2 x

Simplify

= 4 x (x^{2} + 3)

y = arctan (x - 1 + x^{2})

f (x) = x^{3} e^{x}

f (x) = 3 x^{2}, at x = 2

f (x) = 4 e^{- 2 x} - 9 x + 1 (0.5)

4 x - 1

What is the derivative of y=(x^2+3)^2 ?
The derivative of y=(x^2+3)^2 is 4x(x^2+3)
What is the first derivative of y=(x^2+3)^2 ?
The first derivative of y=(x^2+3)^2 is 4x(x^2+3)