What is the derivative of y= 2/(x^2) ?

The derivative of y= 2/(x^2) is -4/(x^3)

What is the first derivative of y= 2/(x^2) ?

The first derivative of y= 2/(x^2) is -4/(x^3)

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derivative of

y = \frac{2}{x ^{2}}

- \frac{4}{x ^{3}}

Solution steps

\frac{d}{d x} (\frac{2}{x ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (\frac{1}{x ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 2 \frac{d}{d x} (x^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 (- 2 x^{- 2 - 1})

Simplify

2 (- 2 x^{- 2 - 1}) : - \frac{4}{x ^{3}}

= - \frac{4}{x ^{3}}

x = \frac{1}{2}

(- 4, 3), (5, - 1)

f (x) = 3 x

(- 1, 1), (4, 5)

y = (x^{3} + x) arcsin (x)

What is the derivative of y= 2/(x^2) ?
The derivative of y= 2/(x^2) is -4/(x^3)
What is the first derivative of y= 2/(x^2) ?
The first derivative of y= 2/(x^2) is -4/(x^3)