What is the tangent of f(x)=2x^2+7x-9,\at x=-3 ?

The tangent of f(x)=2x^2+7x-9,\at x=-3 is y=-5x-27

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tangent of f(x)=2x^2+7x-9,\at x=-3

tangent of

f (x) = 2 x^{2} + 7 x - 9, at x = - 3

y = - 5 x - 27

Solution steps

Find the tangent point:

(- 3, - 12)

Find the slope of

f (x) = 2 x^{2} + 7 x - 9 : \frac{df ( x )}{d x} = 4 x + 7

Compute the slope of

f (x) = 2 x^{2} + 7 x - 9

x = - 3 : m = - 5

Find the line with slope m=

- 5

and passing through

(- 3, - 12) : y = - 5 x - 27

y = - 5 x - 27

f (x) = (2 x + 1)^{2}

(2, - 23)

y = 2 x

y = sin (3 x)

What is the tangent of f(x)=2x^2+7x-9,\at x=-3 ?
The tangent of f(x)=2x^2+7x-9,\at x=-3 is y=-5x-27