What is the derivative of y= 1/(x^2) ?

The derivative of y= 1/(x^2) is -2/(x^3)

What is the first derivative of y= 1/(x^2) ?

The first derivative of y= 1/(x^2) is -2/(x^3)

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derivative of

y = \frac{1}{x ^{2}}

- \frac{2}{x ^{3}}

Solution steps

\frac{d}{d x} (\frac{1}{x ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} (x^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 2 x^{- 2 - 1}

Simplify

- 2 x^{- 2 - 1} : - \frac{2}{x ^{3}}

= - \frac{2}{x ^{3}}

12 x + 6 y = 18

y = 3 x - 4

- x

ln (x + 1) + 3

y = 3 x + 4

What is the derivative of y= 1/(x^2) ?
The derivative of y= 1/(x^2) is -2/(x^3)
What is the first derivative of y= 1/(x^2) ?
The first derivative of y= 1/(x^2) is -2/(x^3)