What is the tangent of y=3arcsin(x),(1/2 , pi/2) ?

The tangent of y=3arcsin(x),(1/2 , pi/2) is y=2sqrt(3)x+pi/2-sqrt(3)

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tangent of y=3arcsin(x),(1/2 , pi/2)

tangent of

y = 3 arcsin (x), (\frac{1}{2}, \frac{π}{2})

y = 23 x + \frac{π}{2} - 3

Solution steps

Find the slope of

y = 3 arcsin (x) : \frac{d y}{d x} = \frac{3}{1 - x ^{2}}

Compute the slope of

y = 3 arcsin (x)

(\frac{1}{2}, \frac{π}{2}) : m = 23

Find the line with slope m=

23

and passing through

(\frac{1}{2}, \frac{π}{2}) : y = 23 x + \frac{π}{2} - 3

y = 23 x + \frac{π}{2} - 3

y = 6 x + 3

y = 2 x + 1

y = x^{3} e^{x}

3 x + 4 y = 12

f (x) = sin (ln (x))

What is the tangent of y=3arcsin(x),(1/2 , pi/2) ?
The tangent of y=3arcsin(x),(1/2 , pi/2) is y=2sqrt(3)x+pi/2-sqrt(3)