What is the tangent of f(x)=ln(x)log_{2}(x),\at x=2 ?

The tangent of f(x)=ln(x)log_{2}(x),\at x=2 is y=x+ln(2)-2

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tangent of f(x)=ln(x)log_{2}(x),\at x=2

tangent

y = x + ln (2) - 2

Solution steps

Find the tangent point:

(2, ln (2))

Find the slope of

f (x) = ln (x) lo g_{2} (x) : \frac{df ( x )}{d x} = \frac{2 ln ( x )}{ln ( 2 ) x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 1

Find the line with slope m=

1

and passing through

(2, ln (2)) : y = x + ln (2) - 2

y = x + ln (2) - 2

What is the tangent of f(x)=ln(x)log_{2}(x),\at x=2 ?
The tangent of f(x)=ln(x)log_{2}(x),\at x=2 is y=x+ln(2)-2