What is the tangent of y=sqrt(x),(1,1) ?

The tangent of y=sqrt(x),(1,1) is y= 1/2 x+1/2

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tangent of y=sqrt(x),(1,1)

tangent of

y = x, (1, 1)

y = \frac{1}{2} x + \frac{1}{2}

Solution steps

Find the slope of

y = x : \frac{d y}{d x} = \frac{1}{2 x}

Compute the slope of

y = x

(1, 1) : m = \frac{1}{2}

Find the line with slope m=

\frac{1}{2}

and passing through

(1, 1) : y = \frac{1}{2} x + \frac{1}{2}

y = \frac{1}{2} x + \frac{1}{2}

(2, \frac{3 π}{4})

f (x) = cos^{2} (x)

f (x) = e^{- x^{2}}

9 x - 3 y = 18

2 x sin (x)

What is the tangent of y=sqrt(x),(1,1) ?
The tangent of y=sqrt(x),(1,1) is y= 1/2 x+1/2