What is the normal of y=(x^2)/(x-1),(0,0) ?

The normal of y=(x^2)/(x-1),(0,0) is x=0

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normal of y=(x^2)/(x-1),(0,0)

normal

x = 0

Solution steps

Find the slope of

y = \frac{x ^{2}}{x - 1} : \frac{d y}{d x} = \frac{x ^{2} - 2 x}{( x - 1 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 0

Compute the slope of the perpendicular line:

m_{p} = \infty

Find the line with slope m=

\infty

and passing through

(0, 0) : x = 0

x = 0

What is the normal of y=(x^2)/(x-1),(0,0) ?
The normal of y=(x^2)/(x-1),(0,0) is x=0