What is the derivative of y=x^3ln(x) ?

The derivative of y=x^3ln(x) is 3x^2ln(x)+x^2

What is the first derivative of y=x^3ln(x) ?

The first derivative of y=x^3ln(x) is 3x^2ln(x)+x^2

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derivative

3 x^{2} ln (x) + x^{2}

Solution steps

\frac{d}{d x} (x^{3} ln (x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{3}, g = ln (x)

= \frac{d}{d x} (x^{3}) ln (x) + \frac{d}{d x} (ln (x)) x^{3}

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= 3 x^{2} ln (x) + \frac{1}{x} x^{3}

\frac{1}{x} x^{3} = x^{2}

= 3 x^{2} ln (x) + x^{2}

What is the derivative of y=x^3ln(x) ?
The derivative of y=x^3ln(x) is 3x^2ln(x)+x^2
What is the first derivative of y=x^3ln(x) ?
The first derivative of y=x^3ln(x) is 3x^2ln(x)+x^2