What is x^2+(y-5)^2=25 ?

The solution to x^2+(y-5)^2=25 is Circle with (a,b)=(0,5),r=5

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x^2+(y-5)^2=25

x^{2} + (y - 5)^{2} = 25

(a, b) = (0, 5), r = 5

Solution steps

x^{2} + (y - 5)^{2} = 25

Rewrite

x^{2} + (y - 5)^{2} = 25

in the form of the standard circle equation

(x - 0)^{2} + (y - 5)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (0, 5), r = 5

2 x - 3 y = 6

f (x) = ln (sin^{2} (x))

(- 9, - 6), (5, - 1)

cos (x)

(4, \frac{2 π}{3})

What is x^2+(y-5)^2=25 ?
The solution to x^2+(y-5)^2=25 is Circle with (a,b)=(0,5),r=5