What is the general solution for sin(2x)+cos(2x)=1 ?

The general solution for sin(2x)+cos(2x)=1 is x=pin,x=pin+pi/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin(2x)+cos(2x)=1

sin (2 x) + cos (2 x) = 1

x = πn, x = πn + \frac{π}{4}

Solution steps

sin (2 x) + cos (2 x) = 1

Rewrite using trig identities

2 sin (2 x + \frac{π}{4}) = 1

Divide both sides by

2

sin (2 x + \frac{π}{4}) = \frac{2}{2}

General solutions for

sin (2 x + \frac{π}{4}) = \frac{2}{2}

2 x + \frac{π}{4} = \frac{π}{4} + 2 πn, 2 x + \frac{π}{4} = \frac{3 π}{4} + 2 πn

Solve

2 x + \frac{π}{4} = \frac{π}{4} + 2 πn : x = πn

Solve

2 x + \frac{π}{4} = \frac{3 π}{4} + 2 πn : x = πn + \frac{π}{4}

x = πn, x = πn + \frac{π}{4}

tan (x) = \frac{3}{3}

- sin (x) = 0

cot (x) + 1 = 0

cos (x) = - \frac{2}{2}

cos (x) (cos (x) - 1) = 0

What is the general solution for sin(2x)+cos(2x)=1 ?
The general solution for sin(2x)+cos(2x)=1 is x=pin,x=pin+pi/4