What is the general solution for sin^2(x)-sin(x)=0 ?

The general solution for sin^2(x)-sin(x)=0 is x= pi/2+2pin,x=2pin,x=pi+2pin

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sin^2(x)-sin(x)=0

sin^{2} (x) - sin (x) = 0

x = \frac{π}{2} + 2 πn, x = 2 πn, x = π + 2 πn

Solution steps

sin^{2} (x) - sin (x) = 0

Solve by substitution

sin (x) = 1, sin (x) = 0

sin (x) = 1 : x = \frac{π}{2} + 2 πn

sin (x) = 0 : x = 2 πn, x = π + 2 πn

Combine all the solutions

x = \frac{π}{2} + 2 πn, x = 2 πn, x = π + 2 πn

sec (x) = - 1

sin^{2} (θ) - cos^{2} (θ) = 1 + cos (θ)

cos (x) sin (x) - 2 cos (x) = 0

csc (x) = - 2

cos^{2} (x) - sin^{2} (x) = 0

What is the general solution for sin^2(x)-sin(x)=0 ?
The general solution for sin^2(x)-sin(x)=0 is x= pi/2+2pin,x=2pin,x=pi+2pin