What is the general solution for cos(x)= 1/2 ,0<= x<= 2pi ?

The general solution for cos(x)= 1/2 ,0<= x<= 2pi is x= pi/3 ,x=(5pi)/3

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cos(x)= 1/2 ,0<= x<= 2pi

cos (x) = \frac{1}{2}, 0 \leq x \leq 2 π

x = \frac{π}{3}, x = \frac{5 π}{3}

Solution steps

cos (x) = \frac{1}{2}, 0 \leq x \leq 2 π

General solutions for

cos (x) = \frac{1}{2}

x = \frac{π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

Solutions for the range

0 \leq x \leq 2 π

x = \frac{π}{3}, x = \frac{5 π}{3}

sec (θ) = 1

sin (θ) + cos (θ) = 0

- cos^{2} (θ) + sin^{2} (θ) = cos (θ) + 1

2 cos (x) = 0

cot (θ) = - 1

What is the general solution for cos(x)= 1/2 ,0<= x<= 2pi ?
The general solution for cos(x)= 1/2 ,0<= x<= 2pi is x= pi/3 ,x=(5pi)/3