What is the general solution for -sin(x)-cos(x)=0 ?

The general solution for -sin(x)-cos(x)=0 is x=(3pi)/4+pin

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-sin(x)-cos(x)=0

- sin (x) - cos (x) = 0

x = \frac{3 π}{4} + πn

Solution steps

- sin (x) - cos (x) = 0

Rewrite using trig identities

- tan (x) - 1 = 0

Move

1

to the right side

- tan (x) = 1

Divide both sides by

- 1

tan (x) = - 1

General solutions for

tan (x) = - 1

x = \frac{3 π}{4} + πn

sec (x) sin (x) - 2 sin (x) = 0

4 cos^{2} (x) = 3

cos (3 x) = - \frac{1}{2}

csc (x) = 0

2 cos^{2} (x) + 5 sin (x) = 4

What is the general solution for -sin(x)-cos(x)=0 ?
The general solution for -sin(x)-cos(x)=0 is x=(3pi)/4+pin