What is the general solution for sqrt(2)sin(θ)+1=0 ?

The general solution for sqrt(2)sin(θ)+1=0 is θ=(5pi)/4+2pin,θ=(7pi)/4+2pin

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sqrt(2)sin(θ)+1=0

2 sin (θ) + 1 = 0

θ = \frac{5 π}{4} + 2 πn, θ = \frac{7 π}{4} + 2 πn

Solution steps

2 sin (θ) + 1 = 0

Move

1

to the right side

2 sin (θ) = - 1

Divide both sides by

2

sin (θ) = - \frac{2}{2}

General solutions for

sin (θ) = - \frac{2}{2}

θ = \frac{5 π}{4} + 2 πn, θ = \frac{7 π}{4} + 2 πn

sin (t) = 0

sin (θ) = 2

sin (x) = \frac{12}{13}

cos (θ) = \frac{3}{5}

sin (x) = - 2

What is the general solution for sqrt(2)sin(θ)+1=0 ?
The general solution for sqrt(2)sin(θ)+1=0 is θ=(5pi)/4+2pin,θ=(7pi)/4+2pin