What is the general solution for sin^2(θ)=cos^2(θ) ?

The general solution for sin^2(θ)=cos^2(θ) is θ= pi/4+pin,θ=(3pi)/4+pin

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sin^2(θ)=cos^2(θ)

sin^{2} (θ) = cos^{2} (θ)

θ = \frac{π}{4} + πn, θ = \frac{3 π}{4} + πn

Solution steps

sin^{2} (θ) = cos^{2} (θ)

Subtract

cos^{2} (θ)

from both sides

sin^{2} (θ) - cos^{2} (θ) = 0

Rewrite using trig identities

- cos (2 θ) = 0

Divide both sides by

- 1

cos (2 θ) = 0

General solutions for

cos (2 θ) = 0

2 θ = \frac{π}{2} + 2 πn, 2 θ = \frac{3 π}{2} + 2 πn

Solve

2 θ = \frac{π}{2} + 2 πn : θ = \frac{π}{4} + πn

Solve

2 θ = \frac{3 π}{2} + 2 πn : θ = \frac{3 π}{4} + πn

θ = \frac{π}{4} + πn, θ = \frac{3 π}{4} + πn

x, sin (x) = 0

cos (θ) = \frac{2}{5}

2 cos^{2} (x) = cos (x)

sin (y) = 0

10 sin^{2} (x) = 10 + 5 cos (x)

What is the general solution for sin^2(θ)=cos^2(θ) ?
The general solution for sin^2(θ)=cos^2(θ) is θ= pi/4+pin,θ=(3pi)/4+pin