What is the general solution for 2sin(3x)+sqrt(3)=0 ?

The general solution for 2sin(3x)+sqrt(3)=0 is x=(4pi)/9+(2pin)/3 ,x=(5pi)/9+(2pin)/3

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Popular >

2sin(3x)+sqrt(3)=0

Solution

2 sin (3 x) + 3 = 0

Solution

x = \frac{4 π}{9} + \frac{2 πn}{3}, x = \frac{5 π}{9} + \frac{2 πn}{3}

Degrees

x = 8 0^{\circ} + 12 0^{\circ} n, x = 10 0^{\circ} + 12 0^{\circ} n

Solution steps

2 sin (3 x) + 3 = 0

Move

3

to the right side

2 sin (3 x) + 3 = 0

Subtract

3

from both sides

2 sin (3 x) + 3 - 3 = 0 - 3

Simplify

2 sin (3 x) = - 3

2 sin (3 x) = - 3

Divide both sides by

2

2 sin (3 x) = - 3

Divide both sides by

2

\frac{2 sin ( 3 x )}{2} = \frac{- 3}{2}

Simplify

sin (3 x) = - \frac{3}{2}

sin (3 x) = - \frac{3}{2}

General solutions for

sin (3 x) = - \frac{3}{2}

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

3 x = \frac{4 π}{3} + 2 πn, 3 x = \frac{5 π}{3} + 2 πn

3 x = \frac{4 π}{3} + 2 πn, 3 x = \frac{5 π}{3} + 2 πn

Solve

3 x = \frac{4 π}{3} + 2 πn : x = \frac{4 π}{9} + \frac{2 πn}{3}

3 x = \frac{4 π}{3} + 2 πn

Divide both sides by

3

3 x = \frac{4 π}{3} + 2 πn

Divide both sides by

3

\frac{3 x}{3} = \frac{\frac{4 π}{3}}{3} + \frac{2 πn}{3}

Simplify

\frac{3 x}{3} = \frac{\frac{4 π}{3}}{3} + \frac{2 πn}{3}

Simplify

\frac{3 x}{3} : x

\frac{3 x}{3}

Divide the numbers:

\frac{3}{3} = 1

= x

Simplify

\frac{\frac{4 π}{3}}{3} + \frac{2 πn}{3} : \frac{4 π}{9} + \frac{2 πn}{3}

\frac{\frac{4 π}{3}}{3} + \frac{2 πn}{3}

\frac{\frac{4 π}{3}}{3} = \frac{4 π}{9}

\frac{\frac{4 π}{3}}{3}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{4 π}{3 \cdot 3}

Multiply the numbers:

3 \cdot 3 = 9

= \frac{4 π}{9}

= \frac{4 π}{9} + \frac{2 πn}{3}

x = \frac{4 π}{9} + \frac{2 πn}{3}

x = \frac{4 π}{9} + \frac{2 πn}{3}

x = \frac{4 π}{9} + \frac{2 πn}{3}

Solve

3 x = \frac{5 π}{3} + 2 πn : x = \frac{5 π}{9} + \frac{2 πn}{3}

3 x = \frac{5 π}{3} + 2 πn

Divide both sides by

3

3 x = \frac{5 π}{3} + 2 πn

Divide both sides by

3

\frac{3 x}{3} = \frac{\frac{5 π}{3}}{3} + \frac{2 πn}{3}

Simplify

\frac{3 x}{3} = \frac{\frac{5 π}{3}}{3} + \frac{2 πn}{3}

Simplify

\frac{3 x}{3} : x

\frac{3 x}{3}

Divide the numbers:

\frac{3}{3} = 1

= x

Simplify

\frac{\frac{5 π}{3}}{3} + \frac{2 πn}{3} : \frac{5 π}{9} + \frac{2 πn}{3}

\frac{\frac{5 π}{3}}{3} + \frac{2 πn}{3}

\frac{\frac{5 π}{3}}{3} = \frac{5 π}{9}

\frac{\frac{5 π}{3}}{3}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{5 π}{3 \cdot 3}

Multiply the numbers:

3 \cdot 3 = 9

= \frac{5 π}{9}

= \frac{5 π}{9} + \frac{2 πn}{3}

x = \frac{5 π}{9} + \frac{2 πn}{3}

x = \frac{5 π}{9} + \frac{2 πn}{3}

x = \frac{5 π}{9} + \frac{2 πn}{3}

x = \frac{4 π}{9} + \frac{2 πn}{3}, x = \frac{5 π}{9} + \frac{2 πn}{3}

Popular Examples

cos(4x)=-(sqrt(3))/2

cos (4 x) = - \frac{3}{2}

2cos(x/3)-sqrt(2)=0

2 cos (\frac{x}{3}) - 2 = 0

tan(2x)-tan(x)=0

tan (2 x) - tan (x) = 0

cot(θ)=sqrt(3)

cot (θ) = 3

sin(x)=0.7

sin (x) = 0.7

Frequently Asked Questions (FAQ)

What is the general solution for 2sin(3x)+sqrt(3)=0 ?
The general solution for 2sin(3x)+sqrt(3)=0 is x=(4pi)/9+(2pin)/3 ,x=(5pi)/9+(2pin)/3