What is the general solution for 1+cos(θ)=1-sin(θ) ?

The general solution for 1+cos(θ)=1-sin(θ) is θ=(3pi)/4+pin

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1+cos(θ)=1-sin(θ)

1 + cos (θ) = 1 - sin (θ)

θ = \frac{3 π}{4} + πn

Solution steps

1 + cos (θ) = 1 - sin (θ)

Subtract

1 - sin (θ)

from both sides

cos (θ) + sin (θ) = 0

Rewrite using trig identities

1 + tan (θ) = 0

Move

1

to the right side

tan (θ) = - 1

General solutions for

tan (θ) = - 1

θ = \frac{3 π}{4} + πn

sin^{2} (x) - 2 sin (x) = 0

2 sin (x) = tan (x)

2 sin (θ) = - 1

1 - cos (x) = sin (x)

sin^{2} (x) = 2 sin (x)

What is the general solution for 1+cos(θ)=1-sin(θ) ?
The general solution for 1+cos(θ)=1-sin(θ) is θ=(3pi)/4+pin