What is the general solution for sin^2(x)-sin(x)-2=0 ?

The general solution for sin^2(x)-sin(x)-2=0 is x=(3pi)/2+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin^2(x)-sin(x)-2=0

sin^{2} (x) - sin (x) - 2 = 0

x = \frac{3 π}{2} + 2 πn

Solution steps

sin^{2} (x) - sin (x) - 2 = 0

Solve by substitution

sin (x) = 2, sin (x) = - 1

sin (x) = 2 :

No Solution

sin (x) = - 1 : x = \frac{3 π}{2} + 2 πn

Combine all the solutions

x = \frac{3 π}{2} + 2 πn

tan (x) - 3 = 0

cos^{2} (θ) - sin^{2} (θ) = 1 - sin (θ)

sin (x) cos (x) = \frac{2}{4}

cos^{2} (x) = 1 + sin (x)

3 sec (θ) + 2 = 0

What is the general solution for sin^2(x)-sin(x)-2=0 ?
The general solution for sin^2(x)-sin(x)-2=0 is x=(3pi)/2+2pin